Hence the least number which leaves remainder 2 when divided by 3, 5, 6, 8, 10 and 12 is 962. On putting the value of k in the (120k+2)
So it can be possible when the value of k is equal to 8 Question also says that the required number is also divisible by the 13 $ \Rightarrow $ LCM of 3, 5, 6, 8, 10 and 12 \Īs question says that the least number leaves remainder 2 when divided by the numbers 3, 5, 6, 8, 10 and 12 The given numbers are 3, 5, 6, 8, 10 and 12
At last put the value of k and find the required least number. Then check for what value of k the number is divisible by 13. Hint: Hint- To find the least number we have to calculate the the LCM of the given numbers first then we will set the number as 120k+2 as in the question given that remainder is 2.
